By Manuel Nunez, Paul Baker, Mercedes G. Merayo
This publication constitutes the refereed complaints of the 21th IFIP WG 6.1 overseas convention on checking out speaking platforms, TESTCOM 2009, and the ninth foreign Workshop on Formal methods to checking out of software program, FATES 2009, together held in Eindhoven, The Netherlands, in November 2009. The thirteen revised complete papers awarded including 6 brief papers have been rigorously chosen from 37 submissions to either occasions. The papers disguise new methods, thoughts, theories, methodologies, instruments, and reviews within the box of trying out of speaking structures and common software program.
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Additional resources for Testing of Software and Communication Systems: 21st IFIP WG 6.1 International Conference, TESTCOM 2009 and 9th International Workshop, FATES 2009, Eindhoven, ... Networks and Telecommunications)
Sample text
However, test-cases were mainly generated using empirical approaches, often without automation. In the last years, the software testing community has started to get involved in the service field. As a consequence, several works have tried to bridge the gap between current practice in service testing and state-of-the-art formal and automated software testing. , their WSDL description [21]. This enables to test operations independently. However, WSDL provides neither a semantic information on services nor a behavioural description of them, which is important in presence of composite (orchestration) services.
Again, the situation can be complicated by another fault, such as a missing input flow between p and T’, in which case T’ will be enabled despite the missing output (Figure 6, right). Testing k-Safe Petri Nets 43 Fig. 6. Missing output flow. Correct situation (left), missing output flow of T (center), and interference by a missing input flow to T’.
Suppose they were not equivalent, that is, PN and PN’ do not have the same set of traces. Since we have only removed a constraint from PN, clearly every trace of PN is also a trace of PN’, therefore PN’ must accept traces that are not accepted by PN. Let Tr be such a trace. Since the only difference between PN and PN’ is fewer input flows on t in PN’, necessarily t is in Tr. e. •t is not marked at that point in PN), or another task t’ can fire in PN’ but not in PN. In the former case, because we have only removed (p,t), it mean that (•t)\p is marked but •t is not, a contradiction with the hypothesis.